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[355467] The result of sorting resources that contains null blank cells is not correct in Remote System Details view.
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1 changed files with 16 additions and 1 deletions
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@ -1,5 +1,5 @@
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/*******************************************************************************
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/*******************************************************************************
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* Copyright (c) 2002, 2010 IBM Corporation and others.
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* Copyright (c) 2002, 2011 IBM Corporation and others.
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* All rights reserved. This program and the accompanying materials
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* All rights reserved. This program and the accompanying materials
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* are made available under the terms of the Eclipse Public License v1.0
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* are made available under the terms of the Eclipse Public License v1.0
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* which accompanies this distribution, and is available at
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* which accompanies this distribution, and is available at
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@ -13,6 +13,7 @@
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*
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*
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* Contributors:
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* Contributors:
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* David McKnight (IBM) - [331986] Sort in Remote System Details view shows wrong results
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* David McKnight (IBM) - [331986] Sort in Remote System Details view shows wrong results
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* David McKnight (IBM) - [355467] The result of sorting resources that contains null blank cells is not correct in Remote System Details view.
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*******************************************************************************/
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*******************************************************************************/
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package org.eclipse.rse.internal.ui.view;
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package org.eclipse.rse.internal.ui.view;
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@ -82,6 +83,11 @@ public class SystemTableViewSorter extends ViewerSorter
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Object name1 = getValueFor(e1, _columnNumber);
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Object name1 = getValueFor(e1, _columnNumber);
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Object name2 = getValueFor(e2, _columnNumber);
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Object name2 = getValueFor(e2, _columnNumber);
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// deal with equal objects
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if (name1 == name2){
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return 0;
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}
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try
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try
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{
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{
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Object n1 = name1;
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Object n1 = name1;
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@ -93,6 +99,15 @@ public class SystemTableViewSorter extends ViewerSorter
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n2 = name1;
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n2 = name1;
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}
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}
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// deal with nulls
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if (n1 == null){
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return -1;
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}
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else if (n2 == null){
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return 1;
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}
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if (n1 instanceof String)
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if (n1 instanceof String)
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{
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{
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return ((String) n1).compareTo((String) n2);
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return ((String) n1).compareTo((String) n2);
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